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Old 26th September 2005 | 15:51
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Miserlou
 
Joined: Jan 2003
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From: The Heart
My method is to find the crosswind component which in this case rounds to 15kts. (35 degrees multiplied by 0.5 (the sine of 30)).
Then divide this by the sixty factor of your airspeed. 95 is a smidge over 1.5 times 60. 15 divided by 1.5 makes a wind correction angle of 10 degrees.

Heading to make good the 185 track=175 degrees.
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