74tweaker,
Your comment,
"And how much force is required or applied in order to rip the engines off in this type of manouver? And how you can predict what the engines will do after they have come off the aircraft?"
Obviously more than enough force was applied to tear the engines from their support structure. This is a fact! If you can't figure out in what direction the engines would be tossed, from a left YAW motion of 10 degrees/second, as reported, you have a problem. The physical location of the engines is a matter of record, and is illustrated by the engine location graphic. This is a fact!
NASA states that the rotational forces in an aircrft wake vortex can attain 300'/sec. I trust you have seen many pictures of wake vortices and are aware of their structure, and will admit that they are quite similiar to the structure of a tornado, except that they lie in a horizontal plane.
If the total left surface area of the vertical stabilizer and rudder are struck, broadside by a force of 0.8 G the aircraft is going to move into a left YAW (10 degrees/second, as reported, a fact!
A left instantaneous YAW will induce an immediate left "Dutch Roll", another fact!
.
Last edited by wsherif1; 22nd Nov 2004 at 06:33.