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Old 17th August 2004 | 02:52
  #39 (permalink)  
grrowler
20 Anniversary
 
Joined: Sep 2002
Posts: 642
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From: Eastside
swh, thanks as always for your informative and practical reply, in this case a yr6 maths lesson.

So I design a new engine and put it onto a new aircraft, I should be able to get ETOPs, because the MTBF would be zero until the engine failed (as you cleverly pointed out, anything multiplied by zero is zero )

But didn't you say;
At design phase there is a theoretical constant MTBF
so then, in your own words, these engines x would have a MTBF other than zero, so do the maths again using any number other than zero for the silly scenario.

Now a serious question on the MTBF formula;
I don't pretend to know much about it, but could you clarify it for me. From what you're saying different operators must have different MTBF's. Is the following then correct?
MTBF = (flying hours*aircraft quantity)(of that operator)/(number of confirmed failures)(of that engine worldwide)
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