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Old 4th Jun 2004, 22:00
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Jinkster
TightYorksherMan
 
Join Date: May 2002
Location: Peak District
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General Nav Problems

If anyone could help me I would be much appreciated.

Many thanks,


1) Given:
Compass Heading = 090º
Deviation = 2ºW
Variation = 12ºE
TAS = 160kts
Whilst maintaining a radial 070 from a VOR station, the aircraft flies at a ground distance of 14nm in 6min. What is the wind velocity?

Answer = 160 degrees/ 50knots

2) An aircraft at FL140, IAS 210kt, OAT – 5C and wind component minus 35 knots, is required in order to cross a reporting point 5 MIN later than planned. Assuming that flight conditions do not change, when 150nm from the reporting point the IAS should be reduced to?

Answer = 20kts

Distance = 150nm
Groundspeed = 210 – 35 = 175kts
So 150nm @ 175kts = 51mins
51 + 5mins = 56mins
56mins @ 150nm = 159kts
159 + 35kts = 194.5kt
194.5kt – 210kt = 15.4kts – why is answer 20kts? What have I done wrong?

3) At 0422, an aircraft at FL370, GS 320kts, is on the direct track to VOR ‘X’ 185nm distant. The aircraft is required to cross VOR ‘X’ at FL80. For a mean rate of descent of 1800 ft/min at a mean groundspeed of 232kt, the latest time to commence descent is?

Answer = 0445

Height to Loose = 37,000 – 8000 = 29,000ft

29,000 / 1800 = 16mins to descend

Any Ideas where I go from here????


4) The two standard parallels of a conical lambert projection are at N10º 40’N and N41º 20’. The constant of the cone is approximately?

Answer given = 0.44

5) An aircraft departing A (N40º 00’ E080º 00’) flies a constant true track of 270º at a groundspeed of 120kt. What are the coordinates of the position after 6hrs?

120 x 6 = 720nm x cos 40 = 551nm / 60 = 9º 11’ – E080º = 70º 49’E – what have I done wrong?

6) Given: A is N55º 000º, B is N54º E010º. The average true course of the great circle is 100º. The true course of the rhumbline at point A is =

Answer given = 100º


7) At latitude 60N the scale of a Mercator projection is 1: 5,000,000. The length of the chart between ‘C’ N60 E008 and ‘D’ N60 W008 is?

Answer given = 17.8cm
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