The great circle bearing of position F longitude 24E from position 27N 8W measured at longitude 8E is 084T
The great circle bearing of E from F, measured at F is 272t
What is the bearing of F from E measured at E and what latitude
is F??
Convergency has changed by 8 degrees in the last third of dlong from 8E to 16E. So going back towards E decrease the GC track by two lots of 8 degrees from 264 (this number came from the reciprocal of 084).
264 - 8 - 8 = 248.
This is your Initial GC track.
Convergency = dlong x sin mlat
Convergency (IGC plus or minus FGC) = dlong x sin mlat
272 - 248 = 24 x sin mlat
24 = 24 x sin mlat
1 = sin mlat
Since sin 90 = 1, the mean lat is the pole!
for that to happen the other lat must be 27 N also
What a question! Not in the exam I hope.
Someonelse check my logic as well please