(Send Clowns, I presume there are gremlins in the email system. I tried emailing these to the address you gave me).
I just haven't got a
ing clue what this question is asking. Can someone decipher the gobbledeygook?
Refer to CAP697 MRJT fig 4.4
Given:
DOM - 35,000kg
Expected Load - 12,000kg
Contingency, approach and hold fuel - 2,500kg
Dep AD elevation - 500 ft
Alt AD elevation - 30 ft
(NB it does actually say "Departure AD elevation". I assume it means "Destination AD elevation")
Find (i) Final Reserve Fuel and (ii) Relevant elevation.
(A) 2360 - Alternate elevation
(A) 1180 - Destination elevation
(A) 1180 - Alternate elevation
(A) 2360 - Destination elevation
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And another one!
A flight has to be made with the SEP1
For the fuel calculation, allow 10lb fuel for start up and taxi, 3 mins and 1 gallon of additional fuel to allow for the climb, 10 mins and no fuel correction for the descent.
Planned flight time (overhead to overhead) is 3h12min
Reserve fuel is 30% of trip fuel
Power setting is 25HG/full throttle @ 2100RPM, 20C lean.
FL70 and OAT is 11C.
(A) 286lb
(B) 268lb
(C) 215kg
(D) 252kg
What did I get? 309lb! Must be doing something wrong... enlightenment would be
most welcome!