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Old 2nd March 2004 | 16:24
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pa28biggles
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The first thing to do is to work out the actual c of g positions.
The length of the MAC is 200, TE - LE, 1000 - 800.
10% of 200 is 20.
So the original c of g is 20 rearward of the MAC LE.
Therefore the actual position is 20+800 = 820.

25% of 200 is 50, so the position of the new c of g is 850, using the same method.

The way that I work out such calculations is to use the following method. It is not what is tought where I am studying, but it is more logical to me because I am not learning a formula, I am actually understanding what is going on.

(New moment of c of g) = (Old moment of c of g) - (moment of where mass is being taken) + (moment of where mass is being added)

Mass moved is unknown.

(Mass X new c of g) = (Mass X old c of g) - (Mass moved X arm of position mass to be taken out of) + (Mass moved X arm of position mass to be added to)

(70000 X 850) = (70000 X 820) - (Mass moved X 400) + (Mass moved X 1200)

59500000 = 57400000 - (400 X Mass moved) + (1200 X Mass moved)

2100000 = 800 X Mass moved
Mass moved = 2625kg
Edited since I forgot to include the mass unit kg.
Hope this helps,
PA28.