I will tackle this all one point at a time:
Bookworm: -
That is entirely the point, Avi8tor. Newton's laws concern velocity, which is a vector quantity. A 180-degree turn requires the same change in momentum, regardless of the steady wind (and in fact, regardless of the frame of reference).
Newton I concerns inertia (state of rest or state of motion) and Newton II covers momentum. Sorry, you are wishing away the physics by saying the momentum is the same regardless of the wind!!
We all agree that the momentum with 60kt headwind/60KIAS is ZERO. If the wind was zero the aircrafts momentum would be the mass X TAS (groundspeed). These are clearly different situations!!!
Intruder: -
First, as soon as the airplane starts the turn, groundspeed will change. But that doesn't matter anyhow...
COURSE IT MATTERS, that the whole crux of the question!!! The Super Cub will have to attain a groundspeed of 85kts by 90-degrees through the turn!! IF the conventional rate/radius maths applies, it would have had to accelerate from 0 to 85kts in 6,5seconds!!!
(Quick explanation for those not in the picture: By 90-degrees through the turn the super cub will have zero headwind component therefore TAS = GS = 60kts. Also it would have had to attain 60kts in the direction of the wind. These two are at vectors are at right angles therefore 60/.707 = 85. If you don’t believe me, draw the picture.)
Also, if it has 0 momentum, why does it need power to remain aloft and maintain that "0" momentum? It is because there are external forces acting on it from the airflow
Totally agreed, all normal thrust/lift/weight/drag remain the same. I think we are in agreement that angle of attack and aerodynamic issues are NOT groundspeed dependant.
The airplane also does not know or care about its ground speed.......
Explain your statement!!! We have CLEALY demonstrated that the Physics is different, and it cannot be wished away!!
If I am wrong, show me the maths!!!