Originally Posted by
mabg88
Any idea if the Altitudes of the charts are rounded up or do they implement the curvature of the Earth in the calculations? I feel that the trigonometry applied for my calculation are off by a good margin compared to the actual altitudes of the published charts.
I suspect it’s relatively simple. The table in Jeppesen for gradient to distance suggests it’s 319’ per nautical mile. If there’s a more complicated formula behind the scenes, it’s not immediately obvious.