I think we are assuming that we have a right angle triangle with the angle between the track of 120° and the meridian being 60°, then cos60° = A/H, then H = A ÷ cos60° = 180/cos60° = 360 NM. Chart distance = 360*6080÷3280*1000*100 / 1,000,000 = 66.7 cm. Not an EASA Q I am aware of, Indian DGCA?
Last edited by Alex Whittingham; 23rd Oct 2023 at 21:15.
Reason: degrees and radians