Hi all. I'm new to this site and have my first question. I'm studying Pooley's book on Navigation. One of the practice exam tests is, for me, difficult. I'll write that question below:
First, this is a question and answer I found on this website that's just like the Pooley's practice exam question:
This was an example given by a member here and he was Wrong!
E.g. An aircraft travels south along the same meridian from latitude 27°30'N to 02°15'S. What is the distance flown in kilometres?
27°30'N + 02°15'S = 29°45'
29°45' x 60 = 1785nm.....................HERE I GET 176700????? 
1785nm x 1.852 = 3305.82 km
The Correct answer, after I saw it and checked it, is:Answer
29 degrees, 45 minutes
60 nm = 1 degree
60 x 29 = 1740 + 45 for the minutes = 1785 nm
Now this is the Pooley's question:
An Aircraft is flying north from and to the following latitudes. I did the math but it's NOT one of the Pooley answers. Can someone tell me what the answer is and how they did that? So many thanks. Tom
05degrees, 30sec South flying to 32 degrees 30sec North
= 37 degrees, 0 minutes My Wrong Answer: 2220 km (37 degrees x 60 for 60 km in every degree of Latitude)