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Islander Vx, Vy, Vxse, Vyse conundrum
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2nd Jan 2004, 21:00
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bookworm
Join Date: Aug 2000
Location: UK
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Quote:
Why is T a maximum for the max rate of climb? A maximum value of T as you have defined it gives max angle of climb, not rate.
Yes sorry, typo. Should be:
For max
angle
of climb, T is maximum and so dT/dv = T'(v) = 0. So T'(Vx) = 0.
bookworm
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