Originally Posted by
oggers
A steeper descent angle does not require a greater acceleration to flare.
Newtonian mechanics teaches from v = a * t , that for a flare performed in a fixed time, the additional acceleration (above standard 1g) is proportional to the vertical speed to be arrested, which in turn is almost exactly proportional to glide angle (because x = sin(x) for small x).
Similarly, if the flare is performed from the same height, then a = v * v / (2 * S) shows that the acceleration goes up as the square of the descent speed - or descent angle, for small angles.
This supports Pilot DAR’s statement that a greater acceleration is required from a steeper glide angle.