Originally Posted by
rusty1983
hello,
unfortunately i got no response on the question above, but maybe someone have a clue of a new one that i got at my last exam.
Even this one i was not able to figure out or find any solution hints in the internet. I really like to meet these sadists who create such questions!
Dist. A - b = 1200nm
psr is 84% of ab
pet is 60% of ab
endurance = 8h24mins
what is the groundspeed from psr to a?
I am going already crazy with these questions...everyone i ask, no one has a clue
pet 60% 720
720 = gsr/(gso +gsr) *1200
gsr/(gso +gsr = 0.6
time to pnr 0.6*8hr 24min = 5hr 2min 24sec approx
gso 200kts with the above time
now 720 = gsr/(gsr +200) * 1200
720gsr + (200 * 720) = 1200gsr
gsr = 144000/480 = 300kts