Thank you guys!
Compressor stall, Sorry I have a doubt about how you get the FPA of 3.41 degrees in your example quoted below. I saw you put the formula in an earlier post but I still don't get it.
I thought to find the angle we could simply take the height divided by the distance divided by 100. For example if you are 3000 feet at 10 nm: 3000/10 = 300 then 300/100 = 3 degrees.
But when I apply this formula with 2280 over 6.3nm /100 I get 3.61. But somehow you get 3.41...
Originally Posted by
compressor stall
When corrected, the aircraft "thinks" it's flying from 2280' (but is actually only 2000') over 6.3nm. It needs to tell itself that it is flying 2280' over 6.3*6072 which is 3.41°