Originally Posted by
plotplot
Well I just got back with a nice big 68% on the KDR sheet
I don't know what it was but I just wasn't in the right mindset this morning for CASA's usual bull**** of asking a question in such a conceited way that you second guess yourself when you know the right answer because of their choice of wording.
Very disappointing result when I only have 6 KDR's in 29 questions. Doesn't help when you flunk both the 3 markers. Was completely stumped by the PSD question where I have been using Higgins' method of process of elimination of multiple choice answers. That's kinda hard when they want the answer written in the box now, so no answers to choose from. The question itself made no sense to me as the total endurance was not going to get the aircraft to it's destination in the first place. If anyone could shed some light on another way of working out PSD's without using the process of elimination method I'd be really appreciative because I'm stumped with that one.
Did get the true altitude one wrong as well. The CR3 is also rendered useless when they want the answer written in a box now. Surely they must have a buffer either side of the exact answer for these q's. If someone could answer this one for me I'd again be very appreciative:
You are overhead Canberra YSCB at A060. YSCB elev is 1886, QNH 1009 and OAT on the ground 0*C
What I did:
Pressure height of a.c. = (1013 - 4) x 30 + 6000 = 6120
ISA dev = -11
6120 - 1886 = 4234
4 x (4234/1000) x 11 = 186
4234 - 186 = 4048AGL.
Can't figure out where I'm going wrong with this.
Re-booked for 2 weeks time...
I'd do it this way:
Pressure height of aerodrome: 1886 + (4 x 30) = 2006
ISA deviation at the aerodrome, calculated with respect to the pressure height: ISA-11
True Altitude Correction: 4 x (height AGL/1000) x ISA dev = 4 x (4114/1000) x (-11)
True Altitude is therefore: 6000 - 181 = 5819 feet
True Height = 5819 - 1886 = 3933 feet AGL.
Good luck with the second attempt
