PPRuNe Forums - View Single Post - Why are jet engines more fuel efficient at high altitude?

25th June 2000 | 15:44

#14 (permalink)

Checkboard

Joined: Aug 1998

: ATPL

Posts: 6,623

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From: Ex-pat Aussie in the UK

Quote:

then the momentum given to the air per second is mv, so Thrust = mv.

F=ma, a is in m/s/s, v = m/s, for momentum per second = ma = mv/s

[This message has been edited by Checkboard (edited 04 July 2000).]