Originally Posted by
PDR1
The second vector diagram shows that it isn't, but it's certainly a commonly-held misunderstanding.
PDR
Your diagram #2 states T=D In that case there would be no net force along the flightpath coming from thrust or drag, so those 2 effectively cancel each other out - correct?.
If so we then only need to ensure lift and weight cancel each other for a steady motion.
W is shown with a rearwards component to the flightpath direction - is that correct?
L is also shown acting with a rearwards component to the flightpath - is that correct?
In that case don't we have an unbalanced set of forces with a net force acting rearwards to the flightpath?
This then cannot be a steady motion could it? - your diagram is showing a situation where the aircraft would be de-accelerating.
ie diagram 2 shows an unbalanced set of forces where there would be an acceleration slowing the aircraft, not a steady, unaccelerated climb.
I have a sneaking suspicion you know this and are wanting to see how far you can pull the wool
