Originally Posted by
Vessbot
I'm not following.
He means this:
Below v1/vr increased thrust = decreased go distance. Because the slower you accelerate the more time will pass and the more distance will be covered before you reach your target speed.
Above v1/vr, increased thrust = increased go distance. Because having reached your target speed you have to rotate, which takes the same amount of time in both OEI and AEO situations - same target angle, same pitch rate - so more speed at this point increases the distance covered.
So technically the shortest go distance would be achieved by TOGA until vr then chop thrust to give zero acceleration, rotate and climb to 35ft at vr. Then accelerate. Pointless information!