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Old 5th April 2018 | 11:05
  #1186 (permalink)  
Alex Whittingham
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Joined: May 1999
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From: Bristol, England
Resolve the forces along the longitudinal axis of the aircraft. In one direction we have thrust plus the 'thrust component of weight', W sine theta where theta is the descent angle. In the other we have drag so:
T + W sine theta = D
or T = D - W sine theta.
substituting,
T = 8500 - (11000*0.5) = 3000 Kg. How did I do?
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