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 Questions If you are a professional pilot or your work involves professional aviation please use this forum for questions. Enthusiasts, please use the 'Spectators Balcony' forum.

 26th Nov 2010, 12:09 #1 (permalink) Thread Starter   Join Date: Sep 2009 Location: Jordan Posts: 70 Glide Slope Angle ? Guys , how do we calculate the glide slope angel if an approach is only given as a gradient ?
 26th Nov 2010, 12:47 #2 (permalink) Join Date: Jun 2006 Location: Australia Posts: 1,113 5.2 percent is three degrees 3.77 degrees is 6.5 percent etc etc
 26th Nov 2010, 12:53 #3 (permalink) Thread Starter   Join Date: Sep 2009 Location: Jordan Posts: 70 Would you explain more plz ? example ?
 26th Nov 2010, 14:38 #4 (permalink) Per Ardua ad Astraeus   Join Date: Mar 2000 Location: UK Posts: 18,606 You have two examples in Tee Emm's post!!! Take sin of angle of GP and multiply by 100. Sin 3 deg = 0.05233 x 100=5.233 For mental arithmetic, divide GP angle by 60 and multiply by 100 3/60= .05 x 100=5 Sin 3.77= 0.06571
 26th Nov 2010, 15:33 #5 (permalink) Thread Starter   Join Date: Sep 2009 Location: Jordan Posts: 70 great,, thank you both ,
 26th Nov 2010, 16:35 #6 (permalink) Join Date: Apr 2004 Location: Dorset UK Age: 64 Posts: 810 Nimer767. Are you working in aviation? If so, I would have hoped you could work this out from the basic trigonometry learnt at school by age 14 or 15. If however you are a young flight simmer then it's good to ask. I hope your school teaches you soon.
 26th Nov 2010, 16:41 #7 (permalink) Join Date: May 2005 Location: UK Age: 69 Posts: 221 dixi188 This sums up this forum. Somebody asks a question, gets an answer, and then somebody like you comes along............good grief.
 30th Nov 2010, 17:39 #8 (permalink) Join Date: Jan 2007 Location: Weston Super Mare/UAE Age: 54 Posts: 380 Don't think anybody has yet hit the right answer; you are all fixating on angles when he asked about 'angels'....!! Hat...coat...ttfn....
 30th Nov 2010, 20:53 #9 (permalink) Thread Starter   Join Date: Sep 2009 Location: Jordan Posts: 70 Captainsmiffy
 30th Nov 2010, 21:27 #10 (permalink) Join Date: Sep 2006 Location: World citizen Posts: 246 3° = 5% = 300' per nm
 24th Dec 2010, 01:40 #11 (permalink) Join Date: Feb 2005 Location: flyover country USA Age: 75 Posts: 4,592 I have to ask how many of the newbies could sit down with an E6B computer and instructions, and actually work through a problem correctly?
 25th Dec 2010, 03:07 #12 (permalink) Join Date: Dec 1998 Location: Escapee from Ultima Thule Posts: 4,196 I think it's fair to say that it's been a while since I could be described as a newbie. However... This sort of problem is tailor made for a whiz wheel. Much quicker to solve with one than using a calculator. On a WW: deg.........% ------ = ------- 60.........10
 25th Dec 2010, 04:33 #13 (permalink) Join Date: Oct 2005 Location: USA Posts: 3,240 Too much math. Save yourself the trouble. Jeppesen has the tables available without having to calculate a darn thing. Same for descent tables and gradients.