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Collision avoidance math?

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Old 31st Jan 2005, 18:41
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Red face Collision avoidance math?

Hi all,

Somebody give me a shove with the simplist way of calculating impact times.

IE. 2 aircraft head on at 550 k see each other at 4 kilometers, now calculate how long until impact.

I realise I need to convert 4 kilometers to NM by multiplying by .54 but from there I go blank.

At one point I could do this but now cannot.

Please help a mental blocked getting annoyed oldtimer.

Thanks.

Happy Landings

Flydaddy.
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Old 31st Jan 2005, 18:52
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4km = 2.16nm
Aircraft closing speed = 550 x 2 = 1100nm/hr

Time to impact = 2.16/1100 = .002 hr or (.002 x 3600) = 7.07 sec
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Old 31st Jan 2005, 19:06
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response

Thanks for the response,

Just one last question, where does the 3600 come from?

Thanks again.

Happy Landings.

Flydaddy
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Old 31st Jan 2005, 19:11
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Number of seconds in one hour ........
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Old 31st Jan 2005, 19:12
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Duh!

See, TOTAL block.

Thanks again.

Happy Landings.

Flydaddy.
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