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-   -   Collision avoidance math? (https://www.pprune.org/professional-pilot-training-includes-ground-studies/161501-collision-avoidance-math.html)

flydaddy 31st Jan 2005 18:41

Collision avoidance math?
 
Hi all,

Somebody give me a shove with the simplist way of calculating impact times.

IE. 2 aircraft head on at 550 k see each other at 4 kilometers, now calculate how long until impact.

I realise I need to convert 4 kilometers to NM by multiplying by .54 but from there I go blank.

At one point I could do this but now cannot.

Please help a mental blocked getting annoyed oldtimer.

Thanks.

Happy Landings

Flydaddy.

reynoldsno1 31st Jan 2005 18:52

4km = 2.16nm
Aircraft closing speed = 550 x 2 = 1100nm/hr

Time to impact = 2.16/1100 = .002 hr or (.002 x 3600) = 7.07 sec

flydaddy 31st Jan 2005 19:06

response
 
Thanks for the response,

Just one last question, where does the 3600 come from?

Thanks again.

Happy Landings.

Flydaddy

reynoldsno1 31st Jan 2005 19:11

Number of seconds in one hour ........ :ok:

flydaddy 31st Jan 2005 19:12

Duh!
 
See, TOTAL block.

Thanks again.

Happy Landings.

Flydaddy.


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