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'Time to station' question
Hi everyone.
Hope you all are doing great. Someone please help me with the following question: Q: While maintaining a constant heading, a relative bearing of 15(deg) doubles in 6 mins. The time taken to the station being used is: A: 3mins B: 6mins C: 12mins According to my working: Time to station = 60 x number of minutes flown / change in bearing number of minutes flown: 6 change in bearing: 15 (because the RB doubles) 60x6/15 = 24mins. How come? |
I read that as 30 degs, or double 15. Must be my English.
Phil |
I read that as 30 degs |
Ah the old "double bow method"!!
Wish I could draw the answer but I hope you can draw what I explain and see the reason behind it. At "A" the relative bearing of the Station "C" is 015 The aircraft flies on a constant heading until the relative bearing has doubled (030 in this case). Call this position "B" Draw a line from A to B to C and back to A which makes a triangle. The angle at "A" is 15 degrees. By simple geometry, the angle at "C" is also 15 degrees. If two angles of a triangle are equal then the sides opposite them are also equal. The line A-B is opposite angle C which is 15 degrees The line B - C is opposite angle A which is also 15 degrees. Therefore A to B = B to C So if it takes 6 minutes to fly from A to B then (assuming constant groundspeed) it will also take 6 minutes to fly from B to C (the station). Far easier with a diagram but I hope that helps. Regards, DFC |
Thank you very much DCC. Helped a lot! :ok:
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@wingless aviator
Your formula is correct if you put your bearing pointer on the 90 degrees index (abeam) and note the bearing change. In your example this formula doesn't apply. I guess DFC's method is the best answer. Regards. |
http://i32.tinypic.com/4tomrk.jpg
I made a quick sketch of the problem. By trigonometry default when B=C then b=c also :) Edit: whoops! That turned out larger than expected. I hope I'm better at flying than computers. Edit2: I see that with regards to one of the previous explanations A and B is swapped but you get the picture. |
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