![]() |
Originally Posted by Noknoipobin
(Post 12069763)
Additional note on calculating ROD/ROC
(More precisely, 3° ≈ 318 ft/NM → GS × 5.3) |
Originally Posted by 400guy2
(Post 12070239)
I think you mean 5.03. No?
Thank you ,I mean it’s actually 5.3, not 5.03. tan 3° = height / distance 0.0524 = X / 6076 (1 NM) → X = 6076 × 0.0524 ≈ 318.4 ft So, over 1 NM the height is about 318 ft. Make 1 NM = 1 minute then→ GS = 60 kt if flying 60 kt → ROD ≈ 318 ft/min If flying at Y kt: ROD = (318 / 60) × Y ≈ Y × 5.3 When we truly understand the actual values, it helps improve our situational awareness and caution. In real operations, it may be difficult to fly exactly at an ROD of 530 (GS × 5.3)(in V/S mode). However, if we are flying at around 500 (GS × 5), we can still anticipate how the aircraft profile will develop. This helps avoid confusion or surprise about why, even with a “correct” ROD (GSx5), the aircraft may appear high. Try looking at an example AIP chart for EGLL. https://cimg5.ibsrv.net/gimg/pprune....b34807b91f.png |
Wondering how I ever got through a 43 year pilot career without these formulae ringing in my head…:ugh:
|
Originally Posted by Noknoipobin
(Post 12070279)
Thank you ,I mean it’s actually 5.3, not 5.03. |
Originally Posted by oceancrosser
(Post 12070652)
Wondering how I ever got through a 43 year pilot career without these formulae ringing in my head…:ugh:
|
I understand your sarcasm. I’m simply explaining this for those who wonder if what I wrote is right or wrong, providing a clear source and reference so it’s not just guesswork. Besides, this isn't difficult at all—it’s just middle school or even upper elementary math. The entrance exams to become a pilot were far harder than this. I’ve been flying for over 30 years and have seen many pilots who still can't operate an FMS and have to rely on their co-pilots, or those who can barely read a chart—yet they’ve all managed to survive or reach retirement.
|
Originally Posted by 400guy2
(Post 12070769)
Right you are. I am embarrassed at my slip and at my gall in offering a correction.
|
Originally Posted by Noknoipobin
(Post 12072394)
I’m sorry for making you feel that way. I was only trying to explain and share a bit more about how I work,so that it’s credible and accurate.Sometimes I may speak too much.
|
Originally Posted by oceancrosser
(Post 12070652)
Wondering how I ever got through a 43 year pilot career without these formulae ringing in my head…:ugh:
Apart from approaches, in the crowded airspace of today you often get asked if you can make a given height (climbing or descending) by a given point or distance. Then its nice to have a handy tool to give a quick answer. Handy being the operative word though. As a slower learner I have always appreciated the simple solution and I agree that some of the examples look anything but at first sight. |
| All times are GMT. The time now is 03:12. |
Copyright © 2026 MH Sub I, LLC dba Internet Brands. All rights reserved. Use of this site indicates your consent to the Terms of Use.