Rate of Climb and Climb Gradient Question
First post…
I have been given some rate of climb and climb gradient data and am having difficulty calculating the true airspeed used. I would really appreciate some advice on where I am going wrong. Example data @ ISA and sea level Gross Climb Gradient = 0.2014 Rate of Climb = 2,590 ft/min or 25.57552 nm/hr My solution ROC = KTAS * sine(Gross Climb Gradient) = KTAS * Gross Climb Gradient (sine dropped due to small angle approximation) Leading to KTAS = ROC / Gross Climb Gradient = 25.57552 / 0.2014 = 126.988 ~= 127 My problem lies with the known indicated airspeed, which is 125 KIAS. Can anyone point me to how 125 KIAS becomes 127 KIAS? |
Edit: Never mind, I see its at ISA/sea level.
|
2kts position error correction?
125 KIAS = 127 KEAS = 127 KTAS @ ISA Sea level |
Climb gradient is vertical speed divided by ground speed, not TAS,
so wind could account for the difference. |
My problem lies with the known indicated airspeed, which is 125 KIAS. Can anyone point me to how 125 KIAS becomes 127 KIAS? 2590fpm x 60 / 6076 = 25.576 kts vertical speed. Inverse Tan (0.2014) = 11.387 degrees. 25.576 / sin(11.387) = 129.5 kTAS. Possible errors, in decreasing order of significance: Pressure error (also known as position error) Trigonometric error by dropping the sine Rounding error in calculation For in-flight purposes, it might look something like this: My airspeed (IAS or TAS will do at sea level) is 125kts. My required climb gradient is just over 20%. 125 x 20 = 2500fpm. I need to achieve just over 2500fpm. |
All times are GMT. The time now is 16:39. |
Copyright © 2024 MH Sub I, LLC dba Internet Brands. All rights reserved. Use of this site indicates your consent to the Terms of Use.