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-   -   Why does an aircraft take off? (https://www.pprune.org/tech-log/499152-why-does-aircraft-take-off.html)

pilotmike 29th Oct 2012 17:52

So far in this thread we've seen 'experts' declaring that "During descent the weight overcomes lift, but some lift is still required to stop the aircraft just plummeting out of the sky." whilst admonishing others for not understanding the "relationship between, speed, and angle of attack over an airfoil." amongst other such muddled misconceptions.

We've also had a L1011 whose engines "can only produce about 70,000 tons of thrust."

All we need to add to the mix now is a converor belt, followed by a downwind turn and we'll all be falling out of the sky, or more likely, falling out of our chairs laughing.

Keep up the good work, and please, please keep the gems of humour coming!

Pelikal 29th Oct 2012 18:33

Well, perhaps I'm missing something obvious here but I thought an aircraft takes off because it (or its inhabitants) want to go somewhere....:\

Lord Spandex Masher 29th Oct 2012 18:47

The Definitive Answer
 
Lift and Thrust

It's a long read but will aid your understanding.

mike-wsm 29th Oct 2012 19:30

Lord Spandex - Many thanks for your kind reference to this erudite work. The final reference in connection with kite-flying is apposite and I would comment that the better behaved lift demons are bred at sea and arrive here on the west wind, as today when I enjoyed particularly good flying. :ok:

barit1 29th Oct 2012 19:58

Max lift implies max G-load - for example in maneuvering, like a tight turn, pullup, or stall recovery.

At takeoff you're only pulling maybe 1.1 G.

BUT - because of the low airspeed, CL is probably highest (or close) at takeoff.

airline man 29th Oct 2012 20:49

Airmann :D

I couldn't beleive how many posts it took to get to the right answer on this thread. :ugh:

PPRuNeUser0171 29th Oct 2012 21:06

Along with several other enthusiasts posts your are deleted and most
banned from the forum. You are the worst type - an accident
junkie/ghoul

Rob PPRuNe Admin

john_tullamarine 29th Oct 2012 23:51

The Definitive Answer

.. now that's let the cat out of the bag ...

Lightning Mate 30th Oct 2012 08:53


or more likely, falling out of our chairs laughing.
I already am!!!

dixi188 30th Oct 2012 08:53

How about the B52 take off.

It's the curvature of the earth that gets it airborne at heavy weights. ;)

aerobat77 30th Oct 2012 09:55

is it not a sweety to see all the mental effusions for a question where the basic answer is quite obvious ?

aicrafts have (on good days) wings attached to the hull- and there is a reason for it.

wikipedia helps a lot :ok:

Aircraft - Wikipedia, the free encyclopedia

cheers !

cwatters 30th Oct 2012 10:39

What is the thrust angle relative to the horizontal at take off?

Google suggests that the A380 engines produce a total thrust of 130,000 kg roughly. If the thrust angle was 20 degrees the vertical component would be

130,000 * sin(20) = 44,000Kg

The aircraft max TOW is around 560,000kg so the vertical component of thrust is about 10% of the total force required to lift off.

glum 30th Oct 2012 12:23

That's the point I made - albeit with a mixup of units for the engines!

barit1 30th Oct 2012 12:50

If you have big enough flaps, rotation is unnecessary:

overstress 30th Oct 2012 15:59

In an airliner's flight profile, lift is greatest at the moment of level-off in the cruise. At all other times in the climb, there is a proportion of the thrust vector acting vertically, despite what Capt Bloggs may say ;)

Of course, if you start pulling 2g turns then that's a different matter :)

pattern_is_full 31st Oct 2012 03:26


Google suggests that the A380 engines produce a total thrust of 130,000 kg roughly. If the thrust angle was 20 degrees the vertical component would be

130,000 * sin(20) = 44,000Kg
Not even that much, since most planes don't rotate much beyond 10 degrees, and certainly not airliners unless they have cast-iron tails (to handle the ensuing tailstrike). Go ahead and try rotating directly to a 20-degree pitchup on the AH the next time you take off and see what happens.... ;)

The typical takeoff and climb angles of all Boeing planes - Bangalore Aviation

More like 10 degrees, which gives 22,100 lbs of "vertical" thrust vector in that calculation.
____________

To me, it just isn't that mysterious or complicated:

First - wings don't just suddenly begin producing lift at V1 or Vr - they are producing some lift at any forward airspeed. The faster you go, the more lift they produce. At just below Vr, they may be producing lift equal to, say, 80% of the aircraft weight, with the remaining 20% keeping the wheels on the ground.

At take-off, you rotate the plane, which increases AoA. Increasing AoA from 0 to 10 degrees increases a generic wing's lift coefficient nearly 3x: File:Lift curve.svg - Wikipedia, the free encyclopedia

3x increase in lift means lift increases quickly from 80% to 240% of aircraft weight - and up you go.

Even a 2° increase in AoA increases lift nearly 50% (and the Buff in that video does rotate about 2° - the nose wheel comes up at about 0:15) - which is enough to increase lift from our assumed 80% of weight, to 120% of weight.

or put even more simply:

Condition 1 - airplane weight > than lift = airplane stays on ground

Condition 2 - airplane weight < than lift = airplane climbs

A plane takes off when the increased AoA of rotation, and subsequent increase in lift, moves the plane from condition 1 to condition 2.

Chu Chu 31st Oct 2012 21:41

Lift at 240% of weight would mean pulling 2.4gs at liftoff. I'm only SLF, but I'd think I'd have noticed that.

Burnie5204 31st Oct 2012 21:54

The description from Pattern is full is also evidenced by the way wings flex upwards more, the faster that an aircraft goes on its take-off run.

overstress 6th Nov 2012 22:53


Lift at 240% of weight would mean pulling 2.4gs at liftoff.
Would you care to explain that statement?

Capt Pit Bull 6th Nov 2012 23:13


Quote:

Lift at 240% of weight would mean pulling 2.4gs at liftoff.
Would you care to explain that statement?
Shouldn't be a surprise.

N = L / W

We clearly do not pull 2.4 g at take off therefore Pattern's analysis is wrong.

Pb


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