Turn path with wind.
 

Does anyone have a path of turn formula that takes into account the wind?

ie. I am about to commence a X degree turn to the right from heading H at V TAS and YYY AoB. The wind is PPP/QQ.

Where will I end up as a PBD from my start point? Assume an instantaneous angle of bank, unless someone can start playing around with integrals with a T second roll rate .... :ooh:

I would like to put this into an excel spreadsheet. I've got about it rather cunkily by working out the nil wind turn path, then moving the end point by the wind vector for the time of the turn, but that's messy. :)

Any takers? Ed Williams doesn't cover this one :}

PS turns will be less 180 degrees.

Adding the wind drift based on time in the turn is the way to do it, I'd say. Shouldn't need to be messy. If it is, perhaps you could post your equations and we could see if they can be cleaned up?