CPL/ATPL Question
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CPL/ATPL Question
Hi,
I have a question that has appeared in DGCA CPL exam, I know the answer is B. 16 o Left – 156Kt. I know it is easy to get this answer using the CX-2.
Can anyone please tell me how to get the answer using a scientific calculator, I know there is a formula but can’t seem to remember it.
Given: TAS = 140Kt, True HDG = 302, W/V 045(T)/45kt, calculate drift angle & GS
Thanks in advance.
I have a question that has appeared in DGCA CPL exam, I know the answer is B. 16 o Left – 156Kt. I know it is easy to get this answer using the CX-2.
Can anyone please tell me how to get the answer using a scientific calculator, I know there is a formula but can’t seem to remember it.
Given: TAS = 140Kt, True HDG = 302, W/V 045(T)/45kt, calculate drift angle & GS
Thanks in advance.
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TAS = 140Kt, True HDG = 302, W/V 045(T)/45kt, calculate drift angle & GS
Crosswind Component = W x Sin (diff between Track and W/V)
= 45 x Sin (103)
= 43.8kts
Head wind Component = W x Cos (diff between Track and W/V)
= 45 x Cos (103)
= -`10 kts.......- stands for Tail wind
so Gs will be TAS +(Headwind comp)= Ground speed
140+(10)=150Kts
drift angle
Tan(theta)= Crosswind component/TAS
= 43.8/140=17.13deg
Wind is from around 5 o clock...therefore ur drifting left i.e. 17Left
i don't care what are the options..these are the accurate figures
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Crosswind Component = W x Sin (diff between Track and W/V)
= 45 x Sin (103)
= 43.8kts
Head wind Component = W x Cos (diff between Track and W/V)
= 45 x Cos (103)
= -`10 kts.......- stands for Tail wind
so Gs will be TAS +(Headwind comp)= Ground speed
140+(10)=150Kts
drift angle
Tan(theta)= Crosswind component/TAS
= 43.8/140=17.13deg
Wind is from around 5 o clock...therefore ur drifting left i.e. 17Left
i don't care what are the options..these are the accurate figures
= 45 x Sin (103)
= 43.8kts
Head wind Component = W x Cos (diff between Track and W/V)
= 45 x Cos (103)
= -`10 kts.......- stands for Tail wind
so Gs will be TAS +(Headwind comp)= Ground speed
140+(10)=150Kts
drift angle
Tan(theta)= Crosswind component/TAS
= 43.8/140=17.13deg
Wind is from around 5 o clock...therefore ur drifting left i.e. 17Left
i don't care what are the options..these are the accurate figures
How we get 103...do explain.
Ty
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Can someone explain how to solve this
Aircraft present Hdg 170 (M), ADF 345 relative. Make 450 intercept of the 355 track out bound. What shall be the Hdg to intercept and ADF indication at the time of intercept
– ADF on intercept (Relative) Intercept Hdg (M)
a) 310 175 b) 040 135 c) 045 130
Ans. c
Aircraft present Hdg 170 (M), ADF 345 relative. Make 450 intercept of the 355 track out bound. What shall be the Hdg to intercept and ADF indication at the time of intercept
– ADF on intercept (Relative) Intercept Hdg (M)
a) 310 175 b) 040 135 c) 045 130
Ans. c
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General nav question
Guys i have a doubt. What is chlat btw these two points....A 71DEG 20MIN north and point B 86deg 45min north (over the north pole). In normal questions i was to just subtract point B from point A but in this question i need to subtract both from 90deg and then add to get ans. Plz explain why so