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Forum: Tech Log
5th Jul 2007, 19:28
Replies: 6
Views: 1,082
Posted By DBate

Capt. Slow

Oh, sorry for that! You are absolutely right - it is gradient, not a slope...

In that case, to find the rate required, multiply the gradient by the GS (or rather TAS).

12% x 540 = 6480'/min.
...
Forum: Tech Log
5th Jul 2007, 18:32
Replies: 6
Views: 1,082
Posted By DBate

For the required rate of descent multiply the...

For the required rate of descent multiply the descent angle by the NM/minute times 100.

Taking your example...

540kt = 9NM/min
12° x 900 = 10800'/min.

But... who would fly a 12° angle...
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