vectors
 

Can anyone help me with a question please, dont know if i can post it here, anyway here it is: if a plane is flying at 124 knots (true airspeed) on a headding of 130 degrees with wind at 225/35. what is the planes true ground speed and track.

Can anyone help me get the angle between the aircraft and the wind to complete the vector triangle, from the book its saying 85 degrees (130-45) but i keep getting 95 degrees.

Get a ruler and protractor and draw it out on a piece of paper. It'll all make sense.

G

Wind triangle
 

Hi,

ok, here is the thing: your wind is FROM 225°, meaning it blows TOWARDS 045°.
So, the angle between 130 (Aircraft) and 045 (Wind) is 85°.

I remember sometimes alos not seeing the obvious from too much staring right at it...

Good luck in your training!

thanks for that, so would i be right in saying that if plane flying at 124 knots on 130 degrees = |ab| @ 124 knots
wind from 225 degrees = |bc| @ 35 knots
line |ca| = ground speed

and angle abc = 95 degrees?

ive worked it out both by maths and by drawing and this is what i get but the book says angle abc is 85 degrees?

is this question from the FTE sample questions ?

what ever happened to the E6B?

Flyingmam,

The book is right. You see the wind vector falls below aircraft's 90 degree line.

This is an important question because its needed when you go flying and want to quickly calculate drift angles in your mind, for example in flying holds.

Immagine four quadrants on the aircraft, each 90 degrees. The origin of the quadrants is the aircraft's heading If the aircraft heads 130, the first quadrant is up to 220. The wind vector falls in 225. This means its in the second quadrant.

Now look at the angles subtended in the second quadrant, disregard the first, and its all there. The angle opposite the tailwind component is 5 degrees and the angle opposite the crosswind component is 85 degrees. I made a quick on sketch on paint to make it clearer:

http://i1186.photobucket.com/albums/.../crosswind.jpg

Interesting question.

I always thought the Relative Wind Angle was a number between 0 & 180, not 0 & 90.

Is there mention of variation in the question?
Is the wind given as True, not Magnetic? Met reports/forecasts are True, ATS reports are Magnetic.
With a variation of 10E, that would make the RWA 85.

no mention of variation,wind speed is true. the question is asking for ground speed and aircraft displacement by the wind.

Thanks for the pic, it helps allot!