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atpl question!
Hei, could somebody please help me with a atpl question on navigation? How you do you calcuate it?
Any help would be greatly appreciated! The great circle distance between position A (59°34.1'N008°08.4'E) and B (30°25.9'N 171°51.6'W) is: A:10800nm B:5400nm C:10800km D:2700nm |
If you look at the longitudes of A and B, you can see that the longitude of B is the anti-meridian of that of A. Therefore, the great circle track between them will be accross the nearest pole. You therefore need to work out the distance from A to the pole, and then from the Pole to B.
We know 1 degree of latitude = 60nm A > pole = 90-59°34.1' = 30°25.9' = 1826nm pole > B = 90-30°25.9' = 59°34.1' = 3574nm Therefore, total distance = 5400nm (B) C89 |
What he said but using Calculate distance and bearing between two Latitude/Longitude points using Haversine formula in JavaScript and CalculateMe.com - Convert Kilometers to Nautical Miles
Here to help :E |
Its been a while! but here we go,
Draw the picture, a polar stereographic picture of the northern hemisphere, looking at your 2 points A and B you are going straight over the top. 1 deg of lat = 60 nm So your calculation is simply a total change in Latitude x 60 Total change in latitude is 90-59°34.1' = 30°25.9' 90-30°25.9' = 59°34.1' add them together and x by 60 = 90x60=5400nm |
Thank you very much, guys! You`ve been of great help!:8
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And remember that once you've passed the exam, you'll never, ever, ever have to do that sort of calculation again.
Possibly the most useless of all ATPL subjects - and that's up against some pretty stiff competition. :ugh: |
A small tip is to add up the longitudes - if they make 180 you know you have to go over the Pole. I'm surprised they haven't got 5400 km in there somewhere.
SXTY - I wasn't exactly going over the Pole in a helicopter but I was using such calculations all the time in N Alberta. phil |
Resurrecting an old question
Hi all, apologies for resurrecting an old question
The solution from Nearly There above was a great help. BTW, what if we were NOT going straight over the top? Let's say 45°N 20°W to 30°N 20° E? What would be the simplest way of calculating this without the complex Haversine... Many thanks! |
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