baobab72
11th Mar 2014, 05:15
Hi folks i understand this topic has been beaten to death, however i just want to make sure one last time i have my wording right.
When the engine is running the sprags are locked into position, the torque is transferred from the outer race integral to the upper sheave to the inner race by the wedging action of the sprags and from the inner race integral to the clutch drive shaft, forward to the mrgb and rearward to the trgb.
If the engine quits, the torque from the clutch drive shaft will exceed the torque from the upper sheave driven by the engine, the sprags will roll, allowing the shaft to spin freely without any drag from the engine.
Is that correct?
Finally, how many bearings are there in the robinson? I counted three: one on the upper sheave, one on the mrgb and one on the trgb, am i missing any?
Many thanks
Baobab72
When the engine is running the sprags are locked into position, the torque is transferred from the outer race integral to the upper sheave to the inner race by the wedging action of the sprags and from the inner race integral to the clutch drive shaft, forward to the mrgb and rearward to the trgb.
If the engine quits, the torque from the clutch drive shaft will exceed the torque from the upper sheave driven by the engine, the sprags will roll, allowing the shaft to spin freely without any drag from the engine.
Is that correct?
Finally, how many bearings are there in the robinson? I counted three: one on the upper sheave, one on the mrgb and one on the trgb, am i missing any?
Many thanks
Baobab72