austrianpilot
14th Nov 2011, 17:49
Hey guys,
There's another question in the test bank, where I can't understand the "correct" answer:
"An aeroplane takes off from A (elevation 800 ft, qfe 1000 hPa) and flies to B (elevation 80 ft, qfe 1020 hPa). The highest ground between A&B is 2550 ft. If the aeroplane flew from A to B at 3000 ft indicated with A's QFE on the subscale, and if the regional QNH was 1026 hPa, the A/C would have (assuming that 1 hPa = 27 ft):
A crashes on the hill 690 ft below the top
-> B flown over the hill at least 1230 ft above the top <-
C flown over the hill at least 960 ft above the top
D crashes on the hill 240 ft below the top"
My way to solve the problem was the following:
QNH at A can be calculated using QFE and elevation -> QNH at A = 1030 hPa. So the A/C flies at a altitude of 3800 ft AMSL. Since the QNH at the hill is 1026, say lower than the QNH at A, the A/C would fly at an altitude of 3692 ft AMSL. This gives a terrain clearance of (3692 ft - 2550 ft) of 1142 ft. So the A/C would fly over the hill at least 960 ft above the top, and not as the software states 1230 ft above the top.
Where's the mistake?
Best regards,
austrianpilot
There's another question in the test bank, where I can't understand the "correct" answer:
"An aeroplane takes off from A (elevation 800 ft, qfe 1000 hPa) and flies to B (elevation 80 ft, qfe 1020 hPa). The highest ground between A&B is 2550 ft. If the aeroplane flew from A to B at 3000 ft indicated with A's QFE on the subscale, and if the regional QNH was 1026 hPa, the A/C would have (assuming that 1 hPa = 27 ft):
A crashes on the hill 690 ft below the top
-> B flown over the hill at least 1230 ft above the top <-
C flown over the hill at least 960 ft above the top
D crashes on the hill 240 ft below the top"
My way to solve the problem was the following:
QNH at A can be calculated using QFE and elevation -> QNH at A = 1030 hPa. So the A/C flies at a altitude of 3800 ft AMSL. Since the QNH at the hill is 1026, say lower than the QNH at A, the A/C would fly at an altitude of 3692 ft AMSL. This gives a terrain clearance of (3692 ft - 2550 ft) of 1142 ft. So the A/C would fly over the hill at least 960 ft above the top, and not as the software states 1230 ft above the top.
Where's the mistake?
Best regards,
austrianpilot