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jhurditch
21st Apr 2010, 05:16
Hi guys,

Can anyone spare some time for my amateur questions on Airspeed and Stall speeds.

I am aware that IAS is the airspeed shown by the ASI. Am I also correct to say that IAS will reduce with altitude? I am trying to find the stall speed for a Q400 (I can't find it published anywhere). To be rough about it, I read in a flight test evaluation article that it stalled at 15000 feet at 102 knots. I would like to therefor find the stall speed for it at sea level so used TAS = IAS sqrt p at sea level on row at altitude. I got round about 128 knots at sea level. I am however surprised that this is higher than the stall speed at altitude. Obviously I am interpreting the information incorrectly. Therefor, is stall speed somehow not related to this velocity at sea level?

Any help is much appreciated (I am in first year Aircraft Engineering)

Cheers

Aviast
21st Apr 2010, 07:21
G'day jhurditch,

I'm no engineer but I think I can answer this one.
Let's say:
the Q400 in question weighs the same at sea level as at FL150
lift is equal to weight in level, unaccelerated flightTherefore we can say that the lift must be the same at both levels.

The lift equation is:

L = CL˝ρV2S

Where:

CL = the coefficient of lift of the wing. This is determined by the designer.
ρ = (rho) the density of the air. We can find this in ICAO Doc 7488. 1.225 kg/m3 at sea level.
V = the true airspeed. According to my Jepp CR-3 (Same as an E6-B) 102 KIAS is equal to 128 KTAS.
S = the surface area of the wing. This is set by the designer (64.1 m3 for the Q400)

Since CL and S are fixed we can ignore them and just say that Lift is proportional to ˝ρV2 which happens to have it's own name: q, or "dynamic pressure". q is the total air pressure at a point minus the static pressure or, in other words: indicated airspeed!

So this is all a roundabout way of saying that Lift is proportional to IAS, therefore the wing at the stalling angle (or any other angle) will produce the same lift at the same IAS. Therefore the stall IAS must be the same at all altitudes!

Am I also correct to say that IAS will reduce with altitude?

The 128 knot figure you calculated would be the TAS which, in nil-wind conditions, would equal the groundspeed. So the Q400 was indicating 102 knots but it was actually moving over the ground at 128 knots. So the answer to your question is: if the pilot maintains the same TAS as s/he climbs then yes, the IAS will decrease as the air density decreases. However, the beauty of it is that if you maintain the same IAS up to higher altitudes you will get a higher TAS! The decreasing air density also affects the engine's ability to maintain the same IAS, but that's another issue...

Like I said: I'm no engineer. This is just me figurin' :}

jhurditch
21st Apr 2010, 08:03
I have been pondering this all day and I now have clarity. Thank you very much for this explanation.
I cant thank you enough.

Cheers

John Farley
21st Apr 2010, 17:58
All that is true if you ignore compressibility effects which are related to mach number.

However wing lifting efficiency is adversely affected by mach number and because the mach number increases as you climb at constant IAS, the stall speed will be higher at altitude. How big an increase is type dependant but it is likely to be a few knots.

Mad (Flt) Scientist
21st Apr 2010, 20:51
All that is true if you ignore compressibility effects which are related to mach number.

However wing lifting efficiency is adversely affected by mach number and because the mach number increases as you climb at constant IAS, the stall speed will be higher at altitude. How big an increase is type dependant but it is likely to be a few knots.

Additional caveat to that last statement - for a relatively thick section or relatively gentle leading edge curvature. Thinner, sharper aerofoils may - depending on the section - show considerably more effect of compressibility.

Trim Stab
22nd Apr 2010, 05:01
And hence autopilots, when climbing at constant speed, switch to climbing at constant mach from an altitude where compressibility is likely to become an issue.

Lightning Mate
22nd Apr 2010, 13:48
Just to put the cat amongst the birdies:


lift is equal to weight in level, unaccelerated flight

Not true.

flapassym
22nd Apr 2010, 16:18
Are you refering to the portion of weight taken centrifugally?

Mad (Flt) Scientist
22nd Apr 2010, 19:21
I believe LM is referring to the fact that the usual conventions for forces on an aircraft are:
Lift - acts normal to the flight path
Drag - acts along the flight path
Weight - acts earthwards
Thrust - if net thrust, acts along the engine axis;
- if ram drag/gross thrust, ram acts along the flight path (as drag), gross thrust acts along the engine axis

Therefore, except at zero angle of attack and zero engine incidence (or an appropriate offsetting combination) there will be a thrust component which resoles normal to the flightpath and thus contribute to (or detracts from) aerodynamic lift.

Bullethead
24th Apr 2010, 02:10
The other vertical component opposing wing generated lift is the downforce greated by the tailplane, more at forward CofG and less with aft CofG.

Regards,
BH.

BOAC
24th Apr 2010, 19:34
Sorry about all this, jhurditch:ugh:

eckhard
24th Apr 2010, 21:41
I once flew in a CJ (C.525 twin jet) with the owner who had asked about 'coffin corner'. We did stalls at FL100, 200, 300 and 400. The stalling IAS was pretty much the same at all altitudes (110 I think).

The CJ has a straight wing, cruises at about 360kts/M0.63. The weight was obviously a bit less at the higher altitudes due to the fuel burned off in the climb.

I was expecting 10 to 15 knots increase at FL400 compared with FL100, due to the effects mentioned, but I guess the actual TAS is just too low to have much compressibility?

Mad (Flt) Scientist
25th Apr 2010, 19:24
I once flew in a CJ (C.525 twin jet) with the owner who had asked about 'coffin corner'. We did stalls at FL100, 200, 300 and 400. The stalling IAS was pretty much the same at all altitudes (110 I think).

The CJ has a straight wing, cruises at about 360kts/M0.63. The weight was obviously a bit less at the higher altitudes due to the fuel burned off in the climb.

I was expecting 10 to 15 knots increase at FL400 compared with FL100, due to the effects mentioned, but I guess the actual TAS is just too low to have much compressibility?

There could be various effects "masking" the compressibility effect. One would be the specific wing section used. Another could be the presence of wing dressing (trips etc).

(On some sections) the Mach effect manifests as a lower stalling AoA with increased Mach; however, that applies to the "natural" stalling AoA i.e. in the absence of trips or artificial devices. If you had a situation where, say, the wing stalls at 16 deg at low Mach, but 14 deg at higher Mach, but you have a stall dressing or system which is designed to activate/be effective at 12 deg AoA, you'll struggle to see the mach effect.

Something like that may have been happening. (Afraid I don't know the details of the CJ wing and stall system, if any)

Trim Stab
26th Apr 2010, 21:08
I was expecting 10 to 15 knots increase at FL400 compared with FL100, due to the effects mentioned, but I guess the actual TAS is just too low to have much compressibility?


Correct - you would only be around M0.3 at stall, which is too low to have any compressibility effects. However, as you say, you climb at around M0.6 in the CJ, which is high enough to give some compressibility effects, so the autopilot (when in FLC mode) switches to mach-hold from about FL200.

Mad (Flt) Scientist
27th Apr 2010, 21:02
@trim_stab

Sorry, but a freestream Mach number of 0.3 can easily show up as a localized Mach number approaching, if not in excess of, sonic, depending on the section. There are some aerofoils out there with VERY definite Mach-dependency, even at M0.2 and below.

WeekendFlyer
27th Apr 2010, 22:06
Just a quick addendum to Aviast's otherwise excellent post:

1/2 rho V^2 has rho decreasing with altitude and V = TAS

1/2 rho0 Vi^2 assumes constant sea-level density and indicated airspeed (Vi), where rho0 = 1.225 kg/m^3)

One reason ASIs use a constant density (ISA sea level density) is that density cannot easily be measured and is also quite difficult to calculate, especially when using a mechanical instrument. Also, it has the handy side effect that for some aircraft (i.e. those that do not experience compressibility to any significant extent), scheduled speeds (e.g. Vs, Va, Vne, etc) are not density dependent and thus not temperature dependent or altitude dependent. Imagine how much harder it would be to operate an aircraft where all the safety-related speeds changed with temperature and altitude! :eek:

Note to the more technically advanced readers of the forum:
I think I am correct in stating that for a given weight and configuration, an aircraft will stall at the same Equivalent Airspeed at any altitude attainable within the flight envelope, but I didn't want to confuse our young questioner with discussions of IAS/CAS/EAS, pressure error corrections and scale altitude corrections! Anyway, for most light aircraft Vi is roughly Ve given the likely instrument errors and residual pressure errors, and provided the mach number is low enough then the Bernoulli's equation for non-compressible flow applies and thus IAS and TAS can be related simply by root sigma. However, I hope the university teaches its students about Bernoulli's equation for compressible flow and all the additional complexity that comes with it! :8

Machdiamond
28th Apr 2010, 13:39
Mach has an effect on maximum lift coefficient but Reynolds number is often the key player.

Actually in the case of the CitationJet, its airfoil is derived from the well studied HS-NLF213. At 100 knots calibrated between sea level and 41000ft you will see the wing Reynolds number go from about 5 million down to 3 million.

If you look at graph 28 in this report (http://ntrs.nasa.gov/archive/nasa/casi.ntrs.nasa.gov/19900003224_1990003224.pdf) you will see that the full flaps 2d maximum lift coefficient drops from 3.7 to almost 3.4 due to the lower Re so this will explain most of the 10-15 knots stall speed increase between those altitudes. A similar effect would be present with flaps up.

As John Farley pointed out, the effect varies considerably between aircraft types. The example given here is on the high side.

As to why you would not see it by yourself in a 525 at 41000ft it probably has to do with airspeed calibration, if the lower fuel weight did not explain it. Certification agencies would be satisfied with a system that indicates constant stall speed as function of altitude even if it is not the case in reality, as long as what is shown to the pilot is the actual margin above stall speed for whatever weight is considered. In other words if your stall speed measurably increases with altitude, you probably want to have your avionics to indicate an airspeed that is such that the pilot does not have to worry about this effect.

galaxy flyer
29th Apr 2010, 13:11
Which brings up the question--shouldn't ADCs output EAS to the ASI, not IAS or CAS?

GF

A37575
30th Apr 2010, 13:45
I should know the answer, but I don't.

In the 737 Classic, a clean approach to the stall at high altitude such as 35-37,000 ft with power at idle, is preceded by really strong buffet well before the stick shaker actuates. The buffet certainly cannot be confused with the type of turbulence experienced with CAT.

A landing flap approach to stall in the circuit with approach thrust, produces no buffet and the stick shaker is the first tactile indication. Why the quite different approach to stall, characteristics?

BOAC
2nd May 2010, 14:29
Already answered by JF and MFS? Wing stalls at lower AoA due to (Mach effect) earlier airflow separation. Stick shake thus 'late' as it is AoA driven.

italia458
6th May 2012, 21:48
Just to add to Machdiamond's reply:

At altitude the Re effect would cause the equivalent stall speed to increase do to changes in the characteristics of the flow over the wing and the resulting decrease in the Clmax. But it would also increase due to compressibility effects. Ignoring Re effect - at altitude, CAS would be higher than EAS.

italia458
8th May 2012, 14:51
If an a/c stalls at sea level at x knots (IAS) then to all intents and purposes, that will be its stall speed in IAS at any altitude.

By adding in "all intents and purposes" you basically cleared your statement from being completely wrong. What does "all intents and purposes" mean? To a 14 year old who just learned about stall speed, I still don't think it would be fair (and definitely not correct) to tell him that IAS stall speed doesn't change. It would be much better to tell him that it remains close to the IAS during most phases of flight but that there are factors that do change the speed at which the wing will stall. Let him explore it more, you might have just sparked some interest in him. To tell him otherwise, you're essentially robbing him of his learning. If you were taught that stall speed never changes than I can understand why you would say that, but if you know that it isn't true, I don't think it's good to lie to the 14 year old... or anyone for that matter.

Society is constantly squashing the natural urge for exploring, learning and creativity. This happens at a very young age and we're basically teaching kids that being wrong is bad. This destroys their urge. Watch this for a little more insight into this: Ken Robinson says schools kill creativity | Video on TED.com (http://www.ted.com/talks/ken_robinson_says_schools_kill_creativity.html)

If a 14 year old can understand (accept) that stall speed is not always the same, why can't someone who is getting their private pilot license?

italia458
8th May 2012, 20:48
sky talk: EAS is a better speed to use to more accurately predict the stall speed at high altitudes. The difference between the EAS and IAS of the stall speed is very small usually. With a new pilot I wouldn't spend too much time talking about the difference but I would tell him that EAS is the most correct 'speed' (mass flow rate) at any speed and that as you increase altitude or speed, EAS will be less than CAS. At slow speeds the difference is small but if I tell the student the truth, he won't be so confused why EAS is significantly lower than CAS at higher speeds and altitudes.... it always is lower!

The only 'true' speed is true airspeed (TAS). All the others are just different measurements of the mass flow rate that goes over the wings.

PhilWebb2
8th May 2012, 21:05
I believe if you check you will find that CAS is always greater than EAS.

PhilWebb2
8th May 2012, 21:07
The problem with using EAS is that you can not read it anywhere on the airspeed indicator. Stick with CAS if you have it because you can read it

italia458
8th May 2012, 22:03
I believe if you check you will find that CAS is always greater than EAS.

That's what I said.

The problem with using EAS is that you can not read it anywhere on the airspeed indicator. Stick with CAS if you have it because you can read it

The problem with CAS is you can't read it on an airspeed indicator. I think you're looking for IAS. Your comment makes no sense.

italia458
9th May 2012, 01:29
shy talk: Um... you're in the "Flight Testing" forum. This forum is described as, "A forum for test pilots, flight test engineers, observers, telemetry and instrumentation engineers and anybody else involved in the demanding and complex business of testing aeroplanes, helicopters and equipment."

What really were you expecting on this forum?!

It's kind of sad that you think that only a test pilot or engineer would know that EAS is less than CAS, considering that it's part of the Private pilot training syllabus to discuss the different speeds from IAS to TAS.