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ARGPILOT
5th Jul 2007, 17:05
airplane desceding a 12% slope while maintaining a GS of 540.

What is the rate of descend aprox?


thanks

Capt. Slow
5th Jul 2007, 18:17
D'oh, very simple, but forgotten how! Isnt it:

G/S(ft per min)*(Glide slope in degrees/60)=Rate of Descent

I keep gettin 6201 ft/min ROD on a 6.8deg slope, which seems unusaully high...

DBate
5th Jul 2007, 18:32
For the required rate of descent multiply the descent angle by the NM/minute times 100.

Taking your example...

540kt = 9NM/min
12° x 900 = 10800'/min.

But... who would fly a 12° angle :confused:

Capt. Slow
5th Jul 2007, 18:38
Wasnt it a 12% gradient and not 12 degree? a little steep!

ray cosmic
5th Jul 2007, 18:45
Space shuttle?

DBate
5th Jul 2007, 19:28
Oh, sorry for that! You are absolutely right - it is gradient, not a slope...

In that case, to find the rate required, multiply the gradient by the GS (or rather TAS).

12% x 540 = 6480'/min.

Regards

Capt. Slow
5th Jul 2007, 19:32
So call it an even 6300' ;) Well your method seems a lot simpler than mine, might adopt that for the future...