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mstram
30th Jun 2006, 23:00
Crusing S&L in your spamcan @ 100kts.

Some abrupt backpressure and one second later you've gained ~60 feet.

Is that ~2g's ? (9.8 m/s /s (~30ft/sec/sec))

If so, if you gained 90 feet after 2 seconds, would that also be 2g's ?

Mike

BOAC
30th Jun 2006, 23:08
s=1/2 at^2

60 = 1/2 x a x 1^2

a=120 / 1

a=120 fpsps

a=4g (probably broken spamcan :) )

After 2 seconds,

a= 180 / 4

a=45 fpsps

a=1.5 g

Bedtime now!

mstram
1st Jul 2006, 00:53
s=1/2 at^2

60 = 1/2 x a x 1^2

a=120 / 1
a=120 fpsps
a=4g (probably broken spamcan :) )
After 2 seconds,
a= 180 / 4
a=45 fpsps
a=1.5 g
Bedtime now!
LOL !
Do you also program with APL ?:ooh:
Any time you feel like adding a few lines of english explanation, that would be great :ok:
Mike

Mad (Flt) Scientist
1st Jul 2006, 04:39
unless you end up still doing S&L flight, some of the height gain comes not from pure vertical accel but from changing the direction of flight.

You can climb at several thousand fpm with less than 1'g', if the flightpath vector points up enough.

cant be bothered working out the physics right now, though ... too many bevvies :)

ICT_SLB
1st Jul 2006, 05:19
cant be bothered working out the physics right now, though ... too many bevvies :)

Happy Canada Day, MFS!

BOAC
1st Jul 2006, 09:08
Apologies, mstram, I assumed you had a basic grasp of physics:)

From Google: http://www.physchem.co.za/Graphs/Equations.htm

Greetings to the colonies:)