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joshiii
12th Feb 2006, 13:41
Hi guys i have a question, 'A helicopter takes off at 1000hours, flies 90 miles and lands on an oil rig. Average outbound speed is 150mph. The return journey is expected to be 20% faster. If the helicopter stays 15mins what time will it arrive back?' i got 1205 using some s=d/t calculations is this right? are you allowed paper to write notes in the test?

pushapproved
12th Feb 2006, 14:06
joshii,

I make the answer 1121, as follows:

If the Helicopter travels 90 miles at 150 mph that flight will take 36 minutes. (90/150 =0.6hrs)

The helicopter is in the rig for 15 minutes.

20% faster on the return leg is 180mph, (150 x 1.2). 90/180 = 0.5hrs

Therefore total time in 36+15+30 = 81 minutes = 1hr 21min

This calculation simply involves s=d/t formula and is fairly 'do-able' in your head but as far as using paper in the OASC selection, I've no idea I'm afraid!

Hope this helps & good luck.

joshiii
12th Feb 2006, 15:37
ahh i see where i went wrong! i didn't convert the 0.5 of an our into 30mins or 0.6 of an hour into 36mins. Cheers