ATPL studies questions CRP Calculations

[CptSilva]

Hi there everyone,

I was thinking that if by any chance is there any website with informations about doing the same calculations of a manual flight computer in regular calculator.
For example:

W/V 050º/15
Track 330º
TAS 80

The anwser is 341º 76kts, this is what we can achieve by manual calculate on the CRP, so if anyone by any chance the formulas to put the same calculations in a normal calculator i would appreciate,


Best regards,

CptSilva

[geraldn]

if for the case of in-flight calculations there is an electronic version of the crap 5,however for the jar ATPL's i recommend u get to know the crp-5 like the back of your hand,since the answers are calculated on it and once u get comfortable with it u will be out of the exam in no time

regards

[Send Clowns]

Why on Earth would you want to? The calculation is extremely straight-forward on a CRP-5, and very complicated on a normal calculator. Why do you want to make things hard for yourself?

[smith]

Draw wind, track and heading vectors on plane paper and measure the distances and angles!! Can't think of any direct formulas off hand.

[High Wing Drifter]

The Max Drift and 'clockface' method produces the same number. Although I wouldn't rely on it for an exam. Not to mention the variations on the theme that crop up such as being given a track and finding the wind. Some of the question specifically expect a whizz wheel technique to produce the answer. The CRP-5 is a one stop shop.

[Whirlygig]

Whilst I appreciate all the answers given and would certainly intend using my CRP-5 for the exams, my natural mathematically curiousity also wondered the same question i.e. the mathematical formulae that would produce the answers.

As a (lapsed) mathematician whose forgotten a lot of it, I think it would help towards my understanding. Although a lot of people shy away from formulae, for some of us it is our second language :8

Cheers

Whirls

[High Wing Drifter]

Well I suppose using Pythag (SOHCAHTOA):

TAS is the hyp G/S the adjacent and wind the opposite.

Sin(Drift) = Wind/TAS = 15/80 = 11deg.

G/S = TAS * Cos(Drift) = 80 * Cos(11) = 78.5kts

It seems correct. Is it?

[Whirlygig]

HWD,

I thought that SOHCAHTOA only worked for right-angled triangles and therefore any Triangle of Velocities had to be broken down into right-angled triangled. I had a bash at doing that one night but failed; I suspect the bottle of Shiraz won.

Cheers

Whirls

[Tinstaafl]

Triangle geometry using the law of sines & law of cosines should do it.

[moo]

or you could try this http://transair.co.uk/product4.asp?SID=2&Product_ID=866

[-IBLB-]

or you could try this http://transair.co.uk/product4.asp?SID=2&Product_ID=866

Are these things allowed for the JAR exams?

[chrisbl]

Not the jAR exams but they are allowed in the FAA exams.

I think the AR in JAR stands for Anally Retentive.:)

[Send Clowns]

Whirly

Indeed I have calculated them, in one case so as to make a spreadsheet. However they are not easy to use, and rather complicated. If we knew why they were wanted we might be able to help more.

[Whirlygig]

Thanks SC, gimme speadsheet NOW!!! Please?

As I said, the main reason that I'm interested is that, as a mathematician (ex), I think it would help my understanding. I know some (including KMS - your comment did NOT go unnoticed!!) find it hard to believe but honestly, I like maths and I would be grateful if someone could refresh my fading memory as to the geometry of the Scalene Triangle!

Cheers

Whirls

[Dick Whittingham]

A over sine a equals B over sine b equals C over sine c

Dick W