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SEAMASTER
24th Jul 2005, 18:03
HELLO GUYS AND GALS,

JUST WONDERING IF ANYONE OUT THERE HAS HIDDEN AWAY IN THE DEEPEST DARKEST CORNER OF THEIR MEMORIES KNOWLEDGE OF RATE/RADIUS OF TURN IN RELATION TO SPEED FLOWN IN THE HOLD. IF MY HOLDING SPEED IS 210KTS WHAT ANGLE OF BANK IS REQUIRED TO MAINTAIN A RATE ONE TURN, ALSO IF THE HOLD DEPICTED IS NOT FLOWN TO AN ADJACENT CROSS CUT RADIAL OR OUTBOUND TO A DME RANGE IS THE STANDARD OUTBOUND LEG 1 MIN +/- WIND EFFECT.

MANY THANKS IN ADVANCE

YOURS

SEAMASTER.

touch&go
24th Jul 2005, 22:49
Divide by 10 + 7so 210/10 + 7 = 28 degrees

1 minute holding FL140 and below and above is 1.5 minutes:D :D :D

BeerMan
25th Jul 2005, 05:44
Hi There,

I actually thought that the equation was your (IAS/10) + 7 equals Rate 1 turn.

For 210kts, that would be (210/10)+7, or 28 degrees AOB.

BeerMan....

monkeyboy
25th Jul 2005, 07:22
And I thought it was Groundspeed / 10 + 7 for a Rate 1?

MB

PropstoMAX
25th Jul 2005, 08:57
Any other offers..
Going once, twice, and the winner is TAS !! :D

Clearedils
25th Jul 2005, 11:18
The max angle of turn should not exceed 25 degrees of bank according to icao doc 8168.

Clearedils

b737-4
25th Jul 2005, 11:48
TAS/10 + 7 with a max of 25!