An A321 has a wingspan of 35.8 m, according to Wikipedia.
Assume it's on the centerline of a 61-meter (200-foot) wide runway.
30.5 m, runway centerline to edge - 17.9, half the wingspan of an A321 = 12.6 m (41 feet), distance from wingtip to runway edge.
An A321 should have a clearance of 12.6 m, or 41 feet, from each wingtip to each edge of the runway.
From the runway edge to the sign that was struck looks like another 75 feet or so, just guessing from the image shown. Let's call it about 22 m.
12.6 m wingtip to runway edge + 22 m runway edge to sign = 34.6 m wingtip to sign.
That would place the sign about 35 m (115 feet) from the wingtip when the aircraft is on centerline.
If all this stuff is correct then that machine must have been quite far off the runway when it hit that sign, about 120 feet laterally displaced on a runway that is 100 feet wide from centerline to edge. Wow!