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Old 4th July 2008, 17:52   #1 (permalink)
brns2
 
Join Date: Apr 2008
Location: Brisbane
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IAS to TAS formula?

Is there any formula to get TAS from a IAS with varying temp or press?

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Old 4th July 2008, 20:18   #2 (permalink)
 
Join Date: May 2000
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Quick formula:

TAS = IAS * [1 + (Altitude/1000 * .02)]

Altitude in feet

Or, TAS = IAS + 2% per 1000' altitude.
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Old 4th July 2008, 22:45   #3 (permalink)
 
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TAS=IAS/sqrt(delta)

where Delta=ratio of air density to ISA SL density
=288.15/(T+273.15) * (P/1013.25)

and P= Ambient pressure in HPa(mB)
T= ambient temperature in degrees celsius

This ignores the compressibility correction, which is very small at low Mach numbers up to about M0.3

The "rule of thumb" correction is actually nearer to 1.5% per 1000' at low altitudes
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Old 5th July 2008, 04:17   #4 (permalink)
 
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From Aviation Formulary V1.43
Mach numbers, true vs calibrated airspeeds etc.

Mach Number (M) = TAS/CS
CS = sound speed= 38.967854*sqrt(T+273.15) where T is the OAT in celsius.
TAS is true airspeed in knots.

Because of compressibility, the measured IAT (indicated air temperature) is higher than the actual true OAT. Approximately:

IAT=OAT+K*TAS^2/7592

The recovery factor K, depends on installation, and is usually in the range 0.95 to 1.0, but can be as low as 0.7. Temperatures are Celsius, TAS in knots.

Also:

OAT = (IAT + 273.15) / (1 + 0.2*K*M^2) - 273.15

The airspeed indicator measures the differential pressure, DP, between the pitot tube and the static port, the resulting indicated airspeed (IAS), when corrected for calibration and installation error is called "calibrated airspeed" (CAS).

For low-speed (M<0.3) airplanes the true airspeed can be obtained from CAS and the density altitude, DA.

TAS = CAS*(rho_0/rho)^0.5=CAS/(1-6.8755856*10^-6 * DA)^2.127940 (DA<36,089.24ft)

Roughly, TAS increases by 1.5% per 1000ft.

When compressibility is taken into account, the calculation of the TAS is more elaborate:

DP=P_0*((1 + 0.2*(IAS/CS_0)^2)^3.5 -1)
M=(5*( (DP/P + 1)^(2/7) -1) )^0.5 (*)
TAS= M*CS

[(*) If this results in M>1 - ie supersonic flight, we have to account for the shock wave ahead of the pitot tube, using Rayliegh's Supersonic Pitot equation.

Using the M from above as the first guess on the RHS, iterate:

M=0.881285 sqrt((DP/P + 1)(1 - 1/(7*M^2))^(5/2))

to convergence.]

P_0 is is (standard) sea-level pressure, CS_0 is the speed of sound at sea-level, CS is the speed of sound at altitude, and P is the pressure at altitude.

These are given by earlier formulae:

P_0= 29.92126 "Hg = 1013.25 mB = 2116.2166 lbs/ft^2
P= P_0*(1-6.8755856*10^-6*PA)^5.2558797, pressure altitude, PA<36,089.24ft
CS= 38.967854*sqrt(T+273.15) where T is the (static/true) OAT in Celsius.
CS_0=38.967854*sqrt(15+273.15)=661.4786 knots

[Example: CAS=250 knots, PA=10000ft, IAT=2°C, recovery factor=0.8
DP=29.92126*((1+0.2*(250/661.4786)^2)^3.5 -1)= 3.1001 "
P=29.92126*(1-6.8755856*10^-6 *10000)^5.2558797= 20.577 "
M= (5*( (3.1001/20.577 +1)^(2/7) -1) )^0.5= 0.4523 Mach
OAT=(2+273.15)/(1 + 0.2*0.8*0.4523^2) - 273.15= -6.72C
CS= 38.967854*sqrt(-6.7+273.15)=636.08 knots
TAS=636.08*0.4523=287.7 knots]

In the reverse direction, given Mach number M and pressure altitude PA, we can find the IAS with:

x=(1-6.8755856e-6*PA)^5.2558797
ias=661.4786*(5*((1 + x*((1 + M^2/5)^3.5 - 1))^(2/7.) - 1))^0.5 (for M <=1)

Some notes on the origins of some of the "magic" number constants in the preceeding section:

6.8755856*10^-6 = T'/T_0, where T' is the standard temperature lapse rate and T_0 is the standard sea-level temperature.

5.2558797 = Mg/RT', where M is the (average) molecular weight of air, g is the acceleration of gravity and R is the gas constant.

0.2233609 = ratio of the pressure at the tropopause to sea-level pressure.

4.806346*10^-5 = Mg/RT_tr, where T_tr is the temperature at the tropopause.

4.2558797 = Mg/RT' -1

0.2970756 = ratio of the density at the tropopause to the density at SL (rho_0)

145442 = T_0/T'

38.967854 = sqrt(gamma R/M) (in knots/Kelvin^0.5), where gamma is the ratio of the specific heats of air
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Old 5th July 2008, 05:18   #5 (permalink)
 
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Hmmm, I usually just read the TAS on the appropriate FD gauge, or look at the FMS.
Works for me...
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Old 5th July 2008, 09:05   #6 (permalink)
 
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wow, thanks for the response guys

Brian Abraham that looks like a really complex way of doing it, but im sure very accurate, but i would probably be at my destination before if figured it out.

I was aware of the TAS=IASx(alt/1000)x0.2 or 0.15......
BUT is there any correction you can make to for ISA temp deviation or ISA MSL press deviation??


thanks
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Old 5th July 2008, 09:27   #7 (permalink)
 
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brns2, sorry but you did ask
Quote:
Is there any formula to get TAS from a IAS with varying temp or press?
Just didn't want you to say I left something out. I'm one of those nerds that wants the answer to the Nth decimal place.
411A, have yet to fly something with a TAS readout, has always been the whiz wheel. The only Lockheed (12A) was so rudimentary it had a morse key in the RHS seat, quite unlike your chariot.
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Old 5th July 2008, 10:54   #8 (permalink)
Mark 1
 
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If it helps:
Every 3 degrees Celsius above ISA approximates to a 1% decrease in delta and a 0.5% increase in TAS correction

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Old 5th July 2008, 17:38   #9 (permalink)
Intruder
 
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IOW, if you're using the rule of thumb in the first place, it just doesn't matter!

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