bank angle for a specific speed
Thread Starter
Join Date: Nov 2005
Location: Scotland
Posts: 35
Likes: 0
Received 0 Likes
on
0 Posts
bank angle for a specific speed
Hi, could anyone tell me the equation for working the bank angle, if speed is given and for a rate 1 turn.
the question is:
An a/c is travelling at 120kts, what angle of bank would be required for a rate one turn?
a) 30 degrees
b) 12 degrees
c) 18 degrees
d) 35 degrees
the answer is 18 degrees, but i cant for the life of me work out how they got the answer.
thanks for your help, CJH
the question is:
An a/c is travelling at 120kts, what angle of bank would be required for a rate one turn?
a) 30 degrees
b) 12 degrees
c) 18 degrees
d) 35 degrees
the answer is 18 degrees, but i cant for the life of me work out how they got the answer.
thanks for your help, CJH
AoB = inv tan .0027463 x TAS in knots
In this case, AoB = inv tan 0.329556 = 18.24 deg
The approximation of (TAS/10) + 7 works pretty well and gives 19 deg
In this case, AoB = inv tan 0.329556 = 18.24 deg
The approximation of (TAS/10) + 7 works pretty well and gives 19 deg
Join Date: Sep 2004
Location: Australia
Age: 52
Posts: 698
Likes: 0
Received 0 Likes
on
0 Posts
inverse tanning...? I reckon!
Haha! Well over here in New Zealand we do it the easy way:
Knock of the zero from the airspeed, and add seven, ie 120 becomes 12, add 7.
18 is the nearest answer (I would bow to anyone who can fly an 18 degree bank angle instead of 19 degrees, haha!!)
Kiwi
Knock of the zero from the airspeed, and add seven, ie 120 becomes 12, add 7.
18 is the nearest answer (I would bow to anyone who can fly an 18 degree bank angle instead of 19 degrees, haha!!)
Kiwi
AoB = inv tan (0.0027463 x (TAS in knots))
i.e., at 120 KTAS:
AoB = inv tan (0.0027463 x 120)
so AoB = inv tan (0.329556)
thus AoB = 18.24 deg
Obviously the (10% TAS) + 7 method is the one to use in flight!
If you want to work it out for yourself, use the formula for radius of turn R = (TAS squared) / (g x tan AoB) and the radius R required to complete a full 360 deg turn in 2 minutes at the TAS in question. Be careful with the units!
i.e., at 120 KTAS:
AoB = inv tan (0.0027463 x 120)
so AoB = inv tan (0.329556)
thus AoB = 18.24 deg
Obviously the (10% TAS) + 7 method is the one to use in flight!
If you want to work it out for yourself, use the formula for radius of turn R = (TAS squared) / (g x tan AoB) and the radius R required to complete a full 360 deg turn in 2 minutes at the TAS in question. Be careful with the units!