View Full Version : Collision avoidance math?


flydaddy
31st Jan 2005, 19:41
Hi all,

Somebody give me a shove with the simplist way of calculating impact times.

IE. 2 aircraft head on at 550 k see each other at 4 kilometers, now calculate how long until impact.

I realise I need to convert 4 kilometers to NM by multiplying by .54 but from there I go blank.

At one point I could do this but now cannot.

Please help a mental blocked getting annoyed oldtimer.

Thanks.

Happy Landings

Flydaddy.



reynoldsno1
31st Jan 2005, 19:52
4km = 2.16nm
Aircraft closing speed = 550 x 2 = 1100nm/hr

Time to impact = 2.16/1100 = .002 hr or (.002 x 3600) = 7.07 sec

flydaddy
31st Jan 2005, 20:06
Thanks for the response,

Just one last question, where does the 3600 come from?

Thanks again.

Happy Landings.

Flydaddy

reynoldsno1
31st Jan 2005, 20:11
Number of seconds in one hour ........ :ok:

flydaddy
31st Jan 2005, 20:12
See, TOTAL block.

Thanks again.

Happy Landings.

Flydaddy.