You can calculate the minimium g if you know the vertical velocity and the "stopping distance". The stopping is roughly the vertical undercarriage travel.
From the equations of motion..
V^2 = U^2 + 2aS
V = final vertical velocity (hopefully zero)
U = Initial velocity (rate of descent at contact)
a = acceleration (will be negative in this case)
S = displacement (undercarriage travel)
This makes a lot of assumptions but it gives the minimium g that will be experienced. In practise the shock absorber won't be linear and I guess it may "bottom out" under high load. That would increase the g considerably.
"a" will be in meters per second. Needs to be divided by 9.8 to get a "g" ratio.
Edit: Report shows this to be irrelevant though. The peak g occured in the air.
Last edited by cwatters; 21st Aug 2009 at 08:43.