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Why are jet engines more fuel efficient at high altitude?
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25th Jun 2000, 15:44
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Checkboard
Join Date: Aug 1998
Location: Ex-pat Aussie in the UK
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then the momentum given to the air
per second
is mv, so Thrust = mv.
F=ma, a is in m/s/s, v = m/s, for momentum per second = ma = mv/s
[This message has been edited by Checkboard (edited 04 July 2000).]
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